Page 185 - og_7den_8e_Mat
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ÜSLÜ İFADELER

                   KONU ANLATIMI



                      1    n      a  –n  b  n
                        = a   ve    (  )  = (  ) dir.
                     a –n        b       a

                   1                        1                     1                     1
                                                                        4
                                                                                                3
                       3
                                                  1
               8)    = 2  = 8                  = 10  = 10       –    = –3  = – 81          = (–2)  = –8
                  2 –3                     10 –1                  3 –4                (–2) –3
                   1                          1                     1                     1
               a)    =                     b)    =              c)  –   =             ç)      =
                  4 –2                       10 –3                  5 –2                (–20) –2


                   7     3                    5                      10                   3
               9)    = 7 · 2  = 56         a)    =              b)  –   =             c)      =
                  2 –3                       10 –2                  10 –1               (–5) –2





                   1   1    –4                1                     1                     1
               10)    =    = 2             a)     =             b)     =              c)  –   =
                  16   2 4                    25                   49                    100




                   2  –2  3  2  9              1  –3                4  –1                 1  –2
               11)  (  ) = (  ) =          a)  (  ) =           b) (  ) =             c)  (  ) =
                   3      2     4              5                    7                    10

                   3
                                                              2
                         3
                                                                      0
                                                                  2
               12)  2  + (–2)  – 1 = 8 + (–8) – 1 = 8 – 8 –1= –1   13)   5  – 7  + 10  = 25 – 49 + 1 = –23
                          3
                                                                      3
                                                                   2
                                                             2
                    3
               a)  –4  + (–3)  + 5 =                     a)   6  – (–4)  – 2  =
                           1    1   3    4   7
                       –1
                   –2
               14)  2  + 3  =    +    =    +    =
                           4    3   12  12  12
                                                              3
                                                                  –2
                   –1
               a)  5  + 2 –2  =                          b)   –2  – 2  + 3 =
                                                              –3 0
                     –4
                                                                   –1
               c)  (–1)  + (–3) –3 =                     ç)   (2 )  – 4 =


                   1   2
                                 3
                            2
               15)    +    = 3  +2 · 2  = 9 + 2 · 8 = 25
                  3 –2  2 –3
                   2   1                                      3   1    5
               a)    –   =                               b)   –2  –    +    =
                  4 –2  5 –1                                     6 –1  10 –2



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